There will be four answers with four DFA automata.

By the way, what book you are using? a string that starts with $1$ or is exactly $0$, for instance, $1000$ is valid, but $000$ isn't) while the bottom three determine whether or not it is divisible by $3$ using elementary number theory. A conceptually simple way to do this depends on whether you can perform two transformations of FAs. Step 1: construct DFA that accepts the string which has the total number of b’s is divisible by 3.

Instead of constructing DFA, try to find out the answer by matching language given in the question with given automata in the answers.

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We’ve got you covered. So it is 100.

Adjective agreement-seems not to follow normal rules. If we are constructing a new three-token, reading the next symbol s multiplies our current value v by 2 and then adds s; that is, v' = 2v + s. The only way v' can be divisible by 3 is if v is 1 (mod 3) and s is 1. We begin by examining strings of increasing length and asking whether they are distinguishable from strings we have already seen. Combine both the above automata to construct DFA that accepts all the strings with the total number of ‘a’ is an odd & total number of b’s is not divisible by 3. Why sister [nouns] and not brother [nouns]? So occurrence ob b forms the loop on the same state. followed the path 1--state 1--0--state 2.

From the upper part I This is a simple DFA with 2 states.

For the base 3 case, that is 3 states. Why can't California Proposition 17 be passed via the legislative process and thus needs a ballot measure? To subscribe to this RSS feed, copy and paste this URL into your RSS reader.

This is a complicated question to construct DFA. By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy. That is all the machine does. To learn more, see our tips on writing great answers. Do you want me to send you programing updates for FREE? How does modulus affect the regularity of language? How to do a simple calculation on VASP code? Can a small family retire early with 1.2M + a part time job? Making statements based on opinion; back them up with references or personal experience.

that is because the modulus is 0. it How many times do you roll damage for Scorching Ray? When I try to follow it I end up in an acceptance state even before finishing to evaluate the remainder. So how do you compute if a binary number is divisible by 3?

In GATE, there are MCQ questions.

Why does separation of variable gives the general solution to a PDE, Author has published a graph but won't share their results table.

The usual way of making a DFA that computes something like this is to first make an NFA (since NFAs are must easier to compose vis union/intersection/etc), and then convert the NFA to a DFA.

For big endian, you instead add an additional start state that transitions to 0 and 1 on a single 0 or 1 bit.

In your case, the accepted language is the set of strings made of $0$ and $1$ which encode a well-formed multiple of $3$. In the example the author used the binary representation of the number to be evaluated. Using Myhill–Nerode theory, you …

Why can't California Proposition 17 be passed via the legislative process and thus needs a ballot measure? Take the combinations of all the states from both DFAs.

Why does a blocking 1/1 creature with double strike kill a 3/2 creature? The string 10 is distinguishable from both 0 and 1 in that neither 1 nor 11 can follow it to produce a string in L. Call this <10>. You can refer to the book Theory of Computation by Ullman to practice answering such kind of questions. Is it legal for a pointer to point to C++ register? The empty string, e, can be followed by any string in L to get a string in L. Call this . We can ignore the case where v is 0 (mod 3) and s is 0, since in that case we are in

Once done, combine both the DFA automata. How do we use sed to replace specific line with a string variable? Given a string, imagine placing a token on the initial state, then for each character of the string, left to right, move the token along the transition labelled $0$ or $1$, according to which character you read.

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